Maharashtra State BoardHSC Science (Electronics) 11th
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Solve the following. The volume of a given mass of a gas at 0°C is 2 dm3. Calculate the new volume of the gas at constant pressure when the temperature is decreased by 10°C. - Chemistry

Numerical

Solve the following.

The volume of a given mass of a gas at 0°C is 2 dm3. Calculate the new volume of the gas at constant pressure when the temperature is decreased by 10°C.

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Solution

Given:

T1 = Initial temperature = 0°C = 0 + 273.15 = 273.15 K,
V1 = Initial volume = 2 dm3
T2 = Final temperature = 273.15 K − 10 = 263.15 K

To find: V2 = Final volume

Formula: `"V"_1/"T"_1="V"_2/"T"_2` (at constant n and P)

Calculation:

According to Charles’ law,

`"V"_1/"T"_1="V"_2/"T"_2` (at constant n and P)

∴ V2 = `("V"_1"T"_2)/"T"_1=(2xx263.15)/273.15` = 1.927 dm3

The new volume of a given mass of gas is 1.927 dm3

Concept: The Gas Laws
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APPEARS IN

Balbharati Chemistry 11th Standard Maharashtra State Board
Chapter 10 States of Matter
Exercises | Q 5. (C)(b) | Page 159
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