Maharashtra State BoardHSC Arts 12th Board Exam
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Solve the following : The following probability distribution of r.v. X X=x -3 -2 -1 0 1 2 3 P(X=x) 0.05 0.1 0.15 0.20 0.25 0.15 0.1 Find the probability that X is odd - Mathematics and Statistics

Sum

Solve the following :

The following probability distribution of r.v. X

X=x -3 -2 -1 0 1 2 3
P(X=x) 0.05 0.10 0.15 0.20 0.25 0.15 0.1

Find the probability that

X is odd

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Solution

P (X is odd)

= P (X = -3) + P (X = -1) + P (x=1) + P (X=3)

= 0.05 + 0.15 + 0.25 + 0.1 = 0.55

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APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) 12th Standard HSC Maharashtra State Board
Chapter 7 Probability Distributions
Miscellaneous Exercise | Q 3.3 | Page 242
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