Sum

Solve the following:

Ten cards numbered 1 to 10 are placed in a box, mixed up thoroughly and then one card is drawn randomly. If it is known that the number on the drawn card is more than 3, what is the probability that it is and even number?

Advertisement Remove all ads

#### Solution

If one card is drawn from the box, the sample space S is given by

S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

∴ n(S) = 10

It is given that number on the card is more than three

∴ the sample space reduces to A= {4, 5, 6, 7, 8, 9, 10}

∴ n(A) = 7

∴ Let B ≡ the event of drawing an even number

∴ B = {2, 4, 6, 8, 10}

∴ A ∩ B = {4, 6, 8, 10}

∴ n(A ∩ B) = 4

∴ The required probability = `"P"("B"/"A")`

= `("n"("A" ∩ "B"))/("n"("A"))`

= `4/7`

Concept: Basic Terminologies

Is there an error in this question or solution?

Advertisement Remove all ads

#### APPEARS IN

Advertisement Remove all ads

Advertisement Remove all ads