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Numerical
Solve the following question:
In an electric circuit, two resistors of 12 0 each are joined in parallel to a 6 V battery. Find the current drawn from the battery.
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Solution
Let net resistance of the given parallel combination be Rnet, Then
`1/"R"_"net"=1/12+1/12`
`1/"R"_"net"= 2/12=1/6`
⇒ Rnet = 6 Ω
Hence, current, `"i"="V"/"R"_"net"=(6"V")/(6 Ω)=1"A"`.
Is there an error in this question or solution?