#### Question

Numerical

**Solve the following question:**

In an electric circuit, two resistors of 12 0 each are joined in parallel to a 6 V battery. Find the current drawn from the battery.

#### Solution

Let net resistance of the given parallel combination be R_{net}, Then

`1/"R"_"net"=1/12+1/12`

`1/"R"_"net"= 2/12=1/6`

⇒ R_{net} = 6 Ω

Hence, current, `"i"="V"/"R"_"net"=(6"V")/(6 Ω)=1"A"`.

Is there an error in this question or solution?

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