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Solve the following problem : The probability that a lamp in the classroom will burn is 0.3. 3 lamps are fitted in the classroom. The classroom is unusable if the number of lamps burning in it is les - Mathematics

Sum

Solve the following problem :

The probability that a lamp in the classroom will burn is 0.3. 3 lamps are fitted in the classroom. The classroom is unusable if the number of lamps burning in it is less than 2. Find the probability that the classroom cannot be used on a random occasion.

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Solution

Let X denote the number of burning lamps.
P(lamp will burn) = p = 0.3
∴ q = 1 – p = 1 – 0.3 = 0.7
Given, n = 3
∴ X ~ B(3, 0.3)
∴ The p.m.f. of X is given by
P(X = x) = `""^3"C"_x (0.3)^x (0.7)^(3 - x), x` = 0, 1, 2, 3
P(Classroom cannot be used)
= P(X < 2)
= P(X = 0 or X = 1)
= P(X = 0) + P(X = 1)
= `""^3"C"_0 (0.3)^0 (0.7)^3 + ""^3"C"_1 (0.3) (0.7)^2`
= (0.7)3 + 3 x (0.3) x (0.7)2
= 0.784

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APPEARS IN

Balbharati Mathematics and Statistics 2 (Commerce) 12th Standard HSC Maharashtra State Board
Chapter 8 Probability Distributions
Part II | Q 1.05 | Page 156
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