Maharashtra State BoardHSC Science (General) 11th
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Solve the following problem. In a random temperature scale X, water boils at 200 °X and freezes at 20 °X. Find the boiling point of a liquid in this scale if it boils at 62 °C. - Physics

Sum

Solve the following problem.

In a random temperature scale X, water boils at 200 °X and freezes at 20 °X. Find the boiling point of a liquid in this scale if it boils at 62 °C.

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Solution

Here thermometric property P is temperature at some random scale X.

Using equation,

T = `(100 ("P"_"T" - "P"_1))/("P"_2 - "P"_1)`

For P1 = 20 °X,
P2 = 200 °X,
T = 62 °C

∴ `62 = (100 ("P"_"T" - 20))/(200 - 20)`

∴ `"P"_"T" = (62 xx (200 - 20))/100 + 20`

= 111.6 + 20

= 131.6 °X

The boiling point of a liquid in this scale is 131.6 °X.

Concept: Measurement of Temperature
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APPEARS IN

Balbharati Physics 11th Standard Maharashtra State Board
Chapter 7 Thermal Properties of Matter
Exercises | Q 3. (viii) | Page 141
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