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Solve the following problem: Find out the molar mass of the following compounds: Mohr’s salt [FeSO4(NH4)2SO4.6H2O] (At. mass: Cu = 63.5; S = 32; O = 16; H = 1; Na = 23; C = 12; Fe = 56; N = 14) - Chemistry

Sum

Solve the following problem:

Find out the molar mass of the following compounds:

Mohr’s salt [FeSO4(NH4)2SO4.6H2O]

(At. mass: Cu = 63.5; S = 32; O = 16; H = 1; Na = 23; C = 12; Fe = 56; N = 14)

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Solution

Molar mass of [FeSO4(NH4)2SO4.6H2O]
= (1 × At. mass Fe) + (2 × At. mass S) + (2 × At. mass N) + (14 × At. mass O) + (20 × At. mass H)
= (1 × 56) + (2 × 32) + (2 × 14) + (14 × 16) + (20 × 1)
= 56 + 64 + 28 + 224 + 20
= 392 g mol–1

Molar mass of [FeSO4(NH4)2SO4.6H2O] = 392 g mol–1

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APPEARS IN

Balbharati Chemistry 11th Standard Maharashtra State Board
Chapter 2 Introduction to Analytical Chemistry
Exercises | Q 4. (D)(c) | Page 24
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