Maharashtra State BoardHSC Science (General) 11th
Advertisement Remove all ads

Solve the following problem: Find out the molar mass of the following compounds: Copper sulphate crystal (CuSO4.5H2O) (At. mass: Cu = 63.5; S = 32; O = 16; H = 1; Na = 23; C = 12; Fe = 56; N = 14) - Chemistry

Sum

Solve the following problem:

Find out the molar mass of the following compounds:

Copper sulphate crystal (CuSO4.5H2O)

(At. mass: Cu = 63.5; S = 32; O = 16; H = 1; Na = 23; C = 12; Fe = 56; N = 14)

Advertisement Remove all ads

Solution

Molar mass of CuSO4.5H2O
= (1 × At. mass Cu) + (1 × At. mass S) + (9 × At. mass O) + (10 × At. mass H)
= (1 × 63.5) + (1 × 32) + (9 × 16) + (10 × 1)
= 63.5 + 32 + 144 + 10
= 249.5 g mol–1

Molar mass of CuSO4.5H2O = 249.5 g mol–1

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Balbharati Chemistry 11th Standard Maharashtra State Board
Chapter 2 Introduction to Analytical Chemistry
Exercises | Q 4. (D)(a) | Page 24
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×