Maharashtra State BoardHSC Science (General) 11th

Solve the following problem. Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 103 km and its mass is 6.4 × 1023 kg. - Physics

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Sum

Solve the following problem.

Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 103 km and its mass is 6.4 × 1023 kg.

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Solution

Given: M = 6.4 × 1023 kg, R = 3.4 × 103 km = 3.4 × 106 m, 

To find: Acceleration due to gravity on the surface of the Mars (gM)

Formula: g = `"GM"/"R"^2`

Calculation: As, G = 6.67 × 10-11 Nm2/kg2

From formula,

`"g"_"M" = (6.67 xx 10^-11 xx 6.4 xx 10^23)/(3.4 xx 10^6)^2 = (6.67 xx 6.4)/(3.4 xx 3.4)`

= antilog{log(6.67) + log(6.4) - log(3.4) - log(3.4)}

= antilog{(0.8241) + (0.8062) - (0.5315) - (0.5315)}

= antilog {0.5673}

= 3.693 m/s2

Acceleration due to gravity on the surface of Mars is 3.693 m/s2.

Concept: Earth Satellites
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APPEARS IN

Balbharati Physics 11th Standard Maharashtra State Board
Chapter 5 Gravitation
Exercises | Q 4. (viii) | Page 99
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