Sum

**Solve the following problem.**

A silver wire has a resistance of 4.2 Ω at 27° C and resistance 5.4 Ω at 100° C. Determine the temperature coefficient of resistance.

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#### Solution

**Given:** R_{1} = 4.2 Ω, R_{2} = 5.4 Ω, T_{1} = 27° C, T_{2} = 100° C

**To find: **Temperature coefficient of resistance (α)

**Formula:** α = `("R"_2-"R"_1)/("R"_1("T"_2-"T"_1))`

**Calculation:** From the formula,

α = `(5.4-4.2)/(4.2(100-27))` = 3.91 × 10^{−3}/° C

The temperature coefficient of resistance is **3.91 × 10 ^{−3}/° C**.

Concept: Specific Resistance (Resistivity)

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