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Solve the following problem. A silver wire has a resistance of 4.2 Ω at 27° C and resistance 5.4 Ω at 100° C. Determine the temperature coefficient of resistance. - Physics

Sum

Solve the following problem.

A silver wire has a resistance of 4.2 Ω at 27° C and resistance 5.4 Ω at 100° C. Determine the temperature coefficient of resistance.

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Solution

Given: R1 = 4.2 Ω, R2 = 5.4 Ω, T1 = 27° C, T2 = 100° C

To find: Temperature coefficient of resistance (α)

Formula: α = `("R"_2-"R"_1)/("R"_1("T"_2-"T"_1))`

Calculation: From the formula,

α = `(5.4-4.2)/(4.2(100-27))` = 3.91 × 10−3/° C

The temperature coefficient of resistance is 3.91 × 10−3/° C.

Concept: Specific Resistance (Resistivity)
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APPEARS IN

Balbharati Physics 11th Standard Maharashtra State Board
Chapter 11 Electric Current Through Conductors
Exercises | Q 4. (vii) | Page 220
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