Sum
Solve the following problem :
A random variable X has the following probability distribution.
x | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
F (x) | k | 2k | 2k | 3k | k2 | 2k2 | 7k2 + k |
Determine P(X < 3)
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Solution
P(X < 3)
= P(X = 1 or X = 2)
= P(X = 1) + P(X = 2)
= k + 2k
= 3k = `(3)/(10)`.
Is there an error in this question or solution?
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