Maharashtra State BoardHSC Commerce 12th Board Exam
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Solve the following problem : A random variable X has the following probability distribution. x 1 2 3 4 5 6 7 F (x) k 2k 2k 3k k2 2k2 7k2 + k Determine P(0 < X < 3) - Mathematics and Statistics

Sum

Solve the following problem :

A random variable X has the following probability distribution.

x 1 2 3 4 5 6 7
F (x) k 2k 2k 3k k2 2k2 7k2 + k

Determine P(0 < X < 3)

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Solution

P(0 < X < 3)
= P(X = 1 or X = 2)
= P(X = 1) + P(X = 2)
= k + 2k
= 3k
= `(3)/(10)`.

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APPEARS IN

Balbharati Mathematics and Statistics 2 (Commerce) 12th Standard HSC Maharashtra State Board
Chapter 8 Probability Distributions
Part I | Q 1.08 | Page 155
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