Maharashtra State BoardHSC Science (Electronics) 11th

Solve the following problem. A planet has mass 6.4 × 1024 kg and radius 3.4 × 106 m. Calculate the energy required to remove an object of mass 800 kg from the surface of the planet to infinity. - Physics

Advertisement Remove all ads
Sum

Solve the following problem.

A planet has mass 6.4 × 1024 kg and radius 3.4 × 106 m. Calculate the energy required to remove an object of mass 800 kg from the surface of the planet to infinity.

Advertisement Remove all ads

Solution

Given: M = 6.4 × 1024 kg, R = 3.4 × 106 m, m = 800 kg

To find: Energy required to remove the object from the surface of planet to infinity = B.E.

Formula: B.E. = `"GMm"/"R"`

Calculation: We know that,

G = 6.67 × 10–11 N m2/kg2

From formula,

B.E. = `(6.67 xx 10^-11 xx 6.4 xx 10^24 xx 800)/(3.4 xx 10^6)`

∴ B.E. =`(6.67 xx 6.4 xx 8)/3.4 xx 10^9`

`= (6.67 xx 51.2)/3.4 xx 10^9`

= antilog{log(6.67) + log(51.2) – log(3.4)} × 109

= antilog{0.8241 + 1.7093 – 0.5315} × 109

= antilog{2.0019} × 109

= 1.004 × 102 × 109

= 1.004 × 1011 J

Energy required to remove the object from the surface of the planet is 1.004 × 1011 J.

Concept: Earth Satellites
  Is there an error in this question or solution?

APPEARS IN

Balbharati Physics 11th Standard Maharashtra State Board
Chapter 5 Gravitation
Exercises | Q 4. (ix) | Page 99
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×