# Solve the following: In a factory which manufactures bulbs, machines A, B and C manufacture respectively 25%, 35% and 40% of the bulbs. Of their outputs, 5, 4 and 2 percent are respectively defective - Mathematics and Statistics

Sum

Solve the following:

In a factory which manufactures bulbs, machines A, B and C manufacture respectively 25%, 35% and 40% of the bulbs. Of their outputs, 5, 4 and 2 percent are respectively defective bulbs. A bulbs is drawn at random from the product and is found to be defective. What is the probability that it is manufactured by the machine B?

#### Solution

Let E1, E2, E3 be the events that bulb is manufactured by machines A, B, C respectively.

E1, E2, E3 are mutually exclusive and exhaustive.

It is given that,

P(E1) = 25% = 25/100, P(E2) = 35% = 35/100, P(E3) = 40% = 40/100

Let D ≡ the event that bulb is defective.

It is given that machines A, B, C have outputs of which 5% 4%, 2% are defective,

∴ "P"("D"/"E"_1) = 5/100, "P"("D"/"E"_2) = 4/100, "P"("D"/"E"_3) = 2/100

By Baye's Theorem, the required probability = "P"("E"_2/"D")

= ("P"("E"_2)*"P"("D"/"E"_2))/("P"("E"_1)*"P"("D"/"E"_1) + "P"("E"_2)*"P"("D"/"E"_2) + "P"("E"_3)*"P"("D"/"E"_3))

= ((35/100)*(4/100))/((25/100)*(5/100) + (35/100)*(4/100) + (40/100)*(2/100))

= 140/(125 + 140 + 80)

= 140/345

= 28/69.

Concept: Baye'S Theorem
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#### APPEARS IN

Balbharati Mathematics and Statistics 1 (Arts and Science) 11th Standard Maharashtra State Board
Chapter 9 Probability
Miscellaneous Exercise 9 | Q II. (22) | Page 215