Answer 1

The given equations can be written in the matrix form as:

`[(1,3),(3,5)][("x"),("y")]=[(2),(4)]`

By R₂ – 3R₁, we get,

`[(1,3),(0,-4)][("x"),("y")]=[(2),(-2)]`

∴ `[("x"+3"y"),(0-4"y")]=[(2),(-2)]`

By equality of matrices,

x + 3y = 2 ........(1)

− 4y = − 2 .............(2)

From (2), y = `1/2`

Substituting y = `1/2` in (1), we get,

x + `3/2` = 2

∴ x = `2-3/2=1/2`

Hence, x = `1/2`, y = `1/2` is the required solution.