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**Solve the following equation:**

`3"a" - 1/5 = "a"/5 + 5 2/5`

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#### Solution

⇒ `"3a" - "a"/5 = 5 2/5 + 1/5`

⇒ `"3a" - "a"/5 = 27/5 + 1/5`

⇒ `"3a" xx 5 - "a"/5 xx 5 = 27/5 xx 5 + 1/5 xx 5`

.....(Multiplying each term by 5)

⇒ 15a - a = 27 + 1

⇒ 14a = 28

⇒ a = `28/14`

⇒ a = 2

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