Question

Solve the following differential equation.

xdx + 2y dy = 0

Answer 1

xdx + 2y dy = 0

Integrating on both sides, we get

`int x dx +2 int y  dy = 0`

∴ `x^2/2 + (2y^2)/2 = c_1`

∴ x² + 2y² = c  .......[2c₁ = c]