# Solve the following differential equation: dydxyxdydx=(1+y)2(1+x)2 - Mathematics and Statistics

Sum

Solve the following differential equation:

"dy"/"dx" = (1 + "y")^2/(1 + "x")^2

#### Solution

"dy"/"dx" = (1 + "y")^2/(1 + "x")^2

∴ 1/(1 + "y"^2) "dy" = 1/(1 + "x"^2) "dx"

Integrating both sides, we get

int 1/(1 + "y"^2) "dx" = int1/(1 + "x"^2) "dx"

∴ tan-1 y = tan-1 x + c

This is the general solution.

Concept: Formation of Differential Equations
Is there an error in this question or solution?