Advertisement
Advertisement
Sum
Solve the following differential equation:
`"dy"/"dx" = (1 + "y")^2/(1 + "x")^2`
Advertisement
Solution
`"dy"/"dx" = (1 + "y")^2/(1 + "x")^2`
∴ `1/(1 + "y"^2) "dy" = 1/(1 + "x"^2) "dx"`
Integrating both sides, we get
`int 1/(1 + "y"^2) "dx" = int1/(1 + "x"^2) "dx"`
∴ tan-1 y = tan-1 x + c
This is the general solution.
Concept: Formation of Differential Equations
Is there an error in this question or solution?
