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Sum

**Solve the following differential equation:**

`"dy"/"dx" = (1 + "y")^2/(1 + "x")^2`

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#### Solution

`"dy"/"dx" = (1 + "y")^2/(1 + "x")^2`

∴ `1/(1 + "y"^2) "dy" = 1/(1 + "x"^2) "dx"`

Integrating both sides, we get

`int 1/(1 + "y"^2) "dx" = int1/(1 + "x"^2) "dx"`

∴ tan^{-1} y = tan^{-1} x + c

This is the general solution.

Concept: Formation of Differential Equations

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