Maharashtra State BoardHSC Science (Electronics) 11th
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Solve the following. Calculate the number of molecules of methane in 0.50 m3 of the gas at a pressure of 2.0 × 102 kPa and a temperature of exactly 300 K. - Chemistry

Sum

Solve the following.

Calculate the number of molecules of methane in 0.50 m3 of the gas at a pressure of 2.0 × 102 kPa and a temperature of exactly 300 K.

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Solution

Given:
V = 0.5 m3,
P = 2.0 × 102 kPa = 2.0 × 105 Pa
T = 300 K,
R = 8.314 J K−1 m−1

To find: Number of molecules of methane gas

Formula: PV = nRT

Calculation: According to ideal gas equation,

n = `"PV"/"RT"`

`n =(2.0xx10^5xx0.5)/(8.314xx300)`

n = 40 mol

Number of molecules = n × NA = 40 × 6.022 × 1023 = 2.4088 × 1025 ≈ 2.409 × 1025

The number of molecules of methane gas present is 2.409 × 1025 molecules.

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APPEARS IN

Balbharati Chemistry 11th Standard Maharashtra State Board
Chapter 10 States of Matter
Exercises | Q 5. (L) | Page 159
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