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Solve the differential equation xdx + 2ydy = 0
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Solution
xdx + 2ydy = 0
Integrating on both sides, we get
`int x "d"x + 2inty "d"y` = 0
∴ `x^2/2 + 2(y^2/2)^2` = c_{1}
∴ x^{2} + 2y^{2} = c, where c = 2c_{1}
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