# Solve the Following Systems of Linear Inequation Graphically: 2x + 3y ≤ 6, X + 4y ≤ 4, X ≥ 0, Y ≥ 0 - Mathematics

Solve the following systems of linear inequation graphically:

2x + 3y ≤ 6, x + 4y ≤ 4, x ≥ 0, y ≥ 0

#### Solution

Converting the inequations to equations, we obtain:
2x + 3y = 6, x + 4y = 4, x = 0, y = 0

2x + 3y =6:  This line meets the x-axis at (3, 0) and the y-axis at (0, 2). Draw a thick line joining these points.
We see that the origin (0,0) satisfies the inequation 2x + 3y ≤ 6.
So, the portion containing  the origin represents the solution set of the inequation 2x + 3y ≤ 6

x + 4y = 4:  This line meets the x-axis at (4, 0) and the y-axis at (0, 1). Draw a thick line joining these points.
We see that the origin (0,0) satisfies the inequation x + 4y ≤ 4.
So, the portion containing  the origin represents the solution set of the inequation x + 4y≤ 4

Clearly, x ≥ 0, y ≥ 0 represents the first quadrant.
Hence, the shaded region in the figure represents the solution set of the given set of inequations.

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#### APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 15 Linear Inequations
Exercise 15.6 | Q 1.2 | Page 30