# Solve the Following Systems of Equations: X/2 + Y = 0.87/(X + Y/2) = 10 - Mathematics

Sum

Solve the following systems of equations:

x/2 + y = 0.8

7/(x + y/2) = 10

#### Solution

The given pair of equation are:
x/2 + y = 0.8             =>x + 2y = 1.6...(a)
7/(x + y/2) = 10        =>7 = 10(x + y/2)        => 7 = 10x + 5y

Lets multiply LHS and RHS of equation (a) by 10 for easy calculation
So, we finally get
10x + 20y = 16 .................(i) And,
10x + 5y = 7.................(ii)

Now, Subtracting two equations we get,
=> (i) - (ii)
15y = 9
=> y = 3/5

Next, putting the value of y in the equation (i) we get,
x = [16 - 20(3/5)]/10

=> (16 - 12)/10 = 4/10

x = 2/5
Thus, the value of x and y obtained are 2/5 and 3/5 respectively.

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Class 10 Maths
Chapter 3 Pair of Linear Equations in Two Variables
Exercise 3.3 | Q 4 | Page 44