Solve the following systems of equations:
`1/(2x) + 1/(3y) = 2`
`1/(3x) + 1/(2y) = 13/6`
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Solution
Let `1/x = u` and `1/y = v` the given equations become
`u/2 + v/3 = 2`
`=> (3u + 2v)/6 = 2`
=> 3u + 2v = 12 .....(i)
And `u/3 + v/2 = 13/6`
`=> (2u + 3v)/6 = 13/6`
`=> v = 6/2 = 3`
Hence `x = 1/u = 1/2` and `y = 1/v = 1/3`
So, the solution of the given system o equation is `x = 1/2, y = 1/3`
Is there an error in this question or solution?
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