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Solve the Following System of Linear Equation Graphically and Shade the Region Between the Two Lines And X-axis: 2x + 3y = 12 X − Y = 1 - Mathematics

Solve the following system of linear equation graphically and shade the region between the two lines and x-axis:

2x + 3y = 12

x − y = 1

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Solution

The given equation is

2x + 3y = 12  ......(i)

x − y = 1  .......(ii)

Putting x = 0 in equation (i) we get

`=> 2xx0 + 3y = 12`

`=> y = 4`

Putting y = 0 in equation (i) we get

`=> 2x + 3 xx 0 = 12`

=> x = 6

x = 6 , y = 0

Use the following table to draw the graph.

x 0 6
y 4 0

Draw the graph by plotting the A(0, 4), B(6,0) two points from table

x - y = 1 ....(ii)

Putting x = 0 in equation (ii) we get

=> 0 - y = 1

=> y = -1

x = 0, y = -1

Putting y = 0 in equation (ii) we get

=> x - 0 = 1

=> x = 1

x = 1, y = 0

Use the following table to draw the graph.

x 0 1
y -1 0

Draw the graph by plotting the two points C(0,-1), D(1,0) from table.

The two lines intersect at P(3,2). The region enclosed by the lines represented by the given equations and x−axis are shown in the above figure

Hence, x = 3 and y = 2 is the solution

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 10 Maths
Chapter 3 Pair of Linear Equations in Two Variables
Exercise 3.2 | Q 24.1 | Page 30
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