# Solve the following simultaneous equations: 7/(2X+1)+13/(Y+2)=27,13/(2X+1)+7/(Y+2)=33 - Algebra

Sum

Solve the following simultaneous equations: 7/(2X+1)+13/(Y+2)=27,13/(2X+1)+7/(Y+2)=33

#### Solution

7/(2x+1)+13/(y+2)=27                             .........(1)

13/(2x+1)+7/(y+2)=33                           ...........(2)

Substituting1/(2x+1)=m and1/(y+2)=n in equations (1) and (2), we get

7m+13n=27    .............(3)

and 13m+7n=33  ..........(4)

Adding equations (3) and (4), we get

20m+20n=60

∴m+n=3      ...............(5)

Subtracting equation (3) from equation (4), we get

6m-6n=6

∴m-n= 1        ...........(6)

Adding equations (5) and (6), we get

2m= 4

∴ m= 2

Substituting m = 2 in equation (5), we get

2 - n= 1

∴ n = 1

Resubstituting the values of m and n, we get

1/(2x+1)=m= 2

⇒ 2x + 1=1/2

⇒ x = (-1)/4

and 1/(y+2)=n =1

⇒ y +2 =1

⇒ y = -1

∴ x=(-1)/4  and y= -1.

Concept: Equations Reducible to a Pair of Linear Equations in Two Variables
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