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Solve the Following Quadratic Equations by Factorization: `Sqrt2x^2-3x-2sqrt2=0` - Mathematics

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Question

Solve the following quadratic equations by factorization:

`sqrt2x^2-3x-2sqrt2=0`

Solution

We have been given

`sqrt2x^2-3x-2sqrt2=0`

`sqrt2x^2-4x+x-2sqrt2=0`

`sqrt2x(x-2sqrt2)+1(x-2sqrt2)=0`

`(x-2sqrt2)(sqrt2x+1)=0`

Therefore,

`x-2sqrt2=0`

`x=2sqrt2`

or,

`sqrt2x+1=0`

`sqrt2x=-1`

`x=(-1)/sqrt2`

Hence, `x=2sqrt2` or `x=(-1)/sqrt2`

  Is there an error in this question or solution?
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APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.3 | Q: 40 | Page no. 20
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.3 | Q: 40 | Page no. 20
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Solution Solve the Following Quadratic Equations by Factorization: `Sqrt2x^2-3x-2sqrt2=0` Concept: Solutions of Quadratic Equations by Factorization.
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