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Solve the Following Quadratic Equations by Factorization: Abx2 + (B2 - Ac)X - Bc = 0 - Mathematics

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Question

Solve the following quadratic equations by factorization:

abx2 + (b2 - ac)x - bc = 0

Solution

We have been given

abx2 + (b2 - ac)x - bc = 0

abx2 + b2x - acx - bc = 0

bx(ax + b) - c(ax + b) = 0

(ax + b)(bx - c) = 0

Therefore,

ax + b = 0

ax = -b

`x=(-b)/a`

or,

bx - c = 0

bx = c

`c = c/b`

Hence, `x=(-b)/a` or `c = c/b`

  Is there an error in this question or solution?
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APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.3 | Q: 55 | Page no. 21
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.3 | Q: 55 | Page no. 21
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Solve the Following Quadratic Equations by Factorization: Abx2 + (B2 - Ac)X - Bc = 0 Concept: Solutions of Quadratic Equations by Factorization.
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