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Solve the following quadratic equation by factorization method: 9x^{2}-25 = 0

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#### Solution

9x^{2}-25=0

(3x)^{2}-(5)^{2}=0

(3x-5)(3x+5)=0……... [a^{2} -b^{2} =(a-b)(a+b)]

(3x-5)=0 or (3x+5)=0

3x = 5 or 3x = -5

x =5/3 or x = -5/3

`therefore{5/3,-5/3} ` is the solution set of the given equation.

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