Question

Solve the following pair of linear equations by the substitution method

`sqrt2x + sqrt3y = 0`

`sqrt3x - sqrt8y = 0`

 

Answer 1

`sqrt2x + sqrt3y = 0`

`sqrt3x - sqrt8y = 0`

From equation (1), we obtain

`x = (-sqrt3y)/sqrt2`

Substituting this value in equation (2), we obtain

`sqrt3(-(sqrt3y)/sqrt2) - sqrt8y = 0`

`-(3y)/sqrt2-2sqrt2y = 0`

`y(-3/sqrt2 - 2sqrt2) = 0`

y = 0   (4)

Substituting this value in equation (3), we obtain x = 0

∴ x= 0, y= 0