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Solve the following pair of linear equations by the substitution method √2x+√3y=0, √3x−√8y=0 - Mathematics

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Solve the following pair of linear equations by the substitution method

`sqrt2x + sqrt3y = 0`

`sqrt3x - sqrt8y = 0`

 

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Solution

`sqrt2x + sqrt3y = 0`

`sqrt3x - sqrt8y = 0`

From equation (1), we obtain

`x = (-sqrt3y)/sqrt2`

Substituting this value in equation (2), we obtain

`sqrt3(-(sqrt3y)/sqrt2) - sqrt8y = 0`

`-(3y)/sqrt2-2sqrt2y = 0`

`y(-3/sqrt2 - 2sqrt2) = 0`

y = 0   (4)

Substituting this value in equation (3), we obtain x = 0

∴ x= 0, y= 0

Concept: Algebraic Methods of Solving a Pair of Linear Equations - Substitution Method
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APPEARS IN

NCERT Class 10 Maths
Chapter 3 Pair of Linear Equations in Two Variables
Exercise 3.3 | Q 1.5 | Page 53
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