Answer 1

The feasible region determined by the constraints, x + 2y ≤ 120, x + y ≥ 60, x − 2y ≥ 0, x ≥ 0, and y ≥ 0, is as follows.

The corner points of the feasible region are A (60, 0), B (120, 0), C (60, 30), and D (40, 20)

The values of Z at these corner points are as follows.

Corner point	Z = 5x + 10y
A(60, 0)	300	→Minimum
B(120, 0)	600	→Maximum
C(60, 30)	600	→Maximum
D(40, 20)	400

The minimum value of Z is 300 at (60, 0).