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Solve the Following Example - SSC (English Medium) Class 8 - Science

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Question

Solve the following example.

When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by 10C. What is the specific heat of the substance?

Solution

Let the specific heat capacity of the substance be c.
Given: Mass of the substance, m = 3 kg = 3000 g
Heat given to the substance, Q = 600 cal
Increase in temperature of the substance = 10C
Now, the amount of heat in a body is given as 

`"Q" = "m" xx "c" xx triangle "T"`

`=> "c" = "Q"/("m" xx triangle "T") = 600/(3000 xx 10) = 0.02  "cal"  g^(-1) ° C^(-1)`

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APPEARS IN

 Balbharati Solution for Balbharati Class 8 Science - General Science (2018 to Current)
Chapter 14: Measurement and Effects of Heat
Exercise | Q: 4.5 | Page no. 103
Solution Solve the Following Example Concept: Concept of Temperature.
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