#### Question

Solve the following example.

A bullet having a mass of 10 g and moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 90 g. The plank was initially at rest. The bullet gets embedded in the plank and both move together. Determine their velocity. (Ans: 0.15 m/s)

#### Solution

Mass of bullet, m_{1 }= 10 g

Initial speed of bullet, u_{1 }= 1.5 m/s

Mass of plank, m_{2 }= 90 g

Initial speed of plank, u_{2 }= 0

From law of conservation of momentum,

m_{1}u_{1 + }m_{2}u_{2} = m_{1}v_{1 }+ m_{2}v_{2}

Since, the bullet gets embedded in the palnk and both move with the same speed, so v_{1 }= v_{2 }= v

So, we can rewrite the equation as

m_{1}u_{1 + }m_{2}u_{2} = (m_{1}_{ }+ m_{2})v

`10 xx 1.5 + 90 xx 0 = (10 + 90)v`

15 = 100 v

⇒ v = 0.15 m/s

Is there an error in this question or solution?

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Solution Solve the Following Example. a Bullet Having a Mass of 10 G and Moving with a Speed of 1.5 M/S, Penetrates a Thick Wooden Plank of Mass 90 G. the Plank Was Initially at Rest. the Bullet Gets Concept: Speed and Velocity.

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