Maharashtra State BoardSSC (English Medium) 8th Standard
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Solve the Following Equations. - Mathematics

Sum

Solve the following equation.

`"y"/7 + "(y-4)/3 = 2`

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Solution

`"y"/7 + "(y-4)/3 = 2`

Multiplying both sides by 21

⇒ 21 `("y"/7)` + 21 `("y" - 4/3)` = 2 x 21

⇒ 3 `("y")` + 7 `("y" - 4)` = 42

⇒ 3y + 7y - 28 = 42

⇒ 10y - 28 = 42

Adding 28 to both sides

⇒ 10y - 28 + 28 = 42 + 28

⇒ 10y = 70

Dividing both sides by 10

⇒ `(10"y")/10 = 70/10`

⇒ y = 7

Hence, y = 7 is the solution of the equation.

Concept: Solution of Equations in One Variable
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APPEARS IN

Balbharati Mathematics 8th Standard Maharashtra State Board
Chapter 12 Equations in one variable
Practice Set 12.1 | Q 2.06 | Page 77
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