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Solve the following equation for x:
`7^(2x+3)=1`
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Solution
`7^(2x+3)=1`
`rArr7^(2x+3)=7^0`
⇒ 2x + 3 = 0
⇒ 2x = -3
`rArrx=-3/2`
Concept: Laws of Exponents for Real Numbers
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