Solve the following equation for x:
`2^(x+1)=4^(x-3)`
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Solution
`2^(x+1)=4^(x-3)`
`rArr2^(x+1)=(2^2)^(x-3)`
`rArr2^(x+1)=(2^(2x-6))`
⇒ x + 1 = 2x - 6
⇒ 2x - x = 1 + 6
⇒ x = 7
Concept: Laws of Exponents for Real Numbers
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