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Solve the equation:`14/(x+3)-1=5/(x+1); xne-3,-1` , for x
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Solution
`14/(x+3)-1=5/(x+1); xne-3,-1`
It can be rewritten as:
`14/(x+3)-5/(x+1)=1`
`(14(x+1)-5(x+3))/((x+1)(x+3))=1`
`(14x+14-5x-15)/(x^2+4x+3)=1`
`(9x-1)/(x^2+4x+3)=1`
On cross multiplying, we get:
9x−1= x2+4x+3
⇒x2−5x+4 = 0
⇒x2−4x−x+4 = 0
⇒x(x−4)− (x−4)=0
⇒(x−1) (x−4)=0
⇒x=1, 4
Thus, the solution of the given equation is 1 or 4.
Concept: Solutions of Quadratic Equations by Factorization
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