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Sum
Solve `(D^3+1)^2y=0`
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Solution
`(D^3+1)^2y=0`
For complementary solution,
f(D) = 0
`therefore(D^3+1)^2=0`
`therefore(D^3+1)=0`
Roots are : `"D"=-1,1/2+isqrt3/2,1/2-isqrt3/2` .. for two times
Roots of given diff. eqn are real and complex.
The general solution of given diff. eqn is given by ,
`y_g=y_c=(c_1+xc_2)e^(-x)+e^(x/2)[(c^3+xc_4)cosx+(c_5+xc_6)sinx`
Concept: Linear Differential Equation with Constant Coefficient‐ Complementary Function
Is there an error in this question or solution?