Sum

Solve `(D^3+1)^2y=0`

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#### Solution

`(D^3+1)^2y=0`

For complementary solution,

f(D) = 0

`therefore(D^3+1)^2=0`

`therefore(D^3+1)=0`

Roots are : `"D"=-1,1/2+isqrt3/2,1/2-isqrt3/2` .. for two times

Roots of given diff. eqn are real and complex.

The general solution of given diff. eqn is given by ,

`y_g=y_c=(c_1+xc_2)e^(-x)+e^(x/2)[(c^3+xc_4)cosx+(c_5+xc_6)sinx`

Concept: Linear Differential Equation with Constant Coefficient‐ Complementary Function

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