Solve: ("6x" + 1)/2 + 1 = ("7x" - 3)/3 - Mathematics

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Sum

Solve: `("6x" + 1)/2 + 1 = ("7x" - 3)/3`

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Solution

`("6x" + 1)/2 + 1 = ("7x" - 3)/3`


`=> ((6"x" + 1) + 1 xx 2)/2 = ("7x" - 3)/3`


`=> ("6x" + 1 + 2)/2 = ("7x" - 3)/3`


`=> ("6x" + 3)/2 = ("7x" - 3)/3`

⇒ 3(6x + 3) = 2(7x - 3)

⇒ 18x + 9 = 14x - 6

⇒ 18x - 14x = - 6 - 9

⇒ 4x = -15

∴ x = `(-15)/4`

Concept: Solving Linear Inequations
  Is there an error in this question or solution?
Chapter 14: Linear Equations in one Variable - Exercise 14 (C) [Page 170]

APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 14 Linear Equations in one Variable
Exercise 14 (C) | Q 1.14 | Page 170

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