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Sum
Solve 2x + 3y = 11 and 2x – 4y = – 24 and hence find the value of ‘m’ for which y = mx + 3.
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Solution
We have,
2x + 3y = 11 ….(1)
2x – 4y = – 24 ….(2)
From (1), we have 2x = 11 – 3y
Substituting 2x = 11 – 3y in (2), we get
11 – 3y – 4y = –24
⇒ –7y = – 24 – 11
⇒ –7y = – 35
⇒ y = 5
Putting y = 5 in (1), we get
2x + 3 × 5 = 11
2x = 11 – 15
⇒ x = –4/2 = – 2
Hence, x = – 2 and y = 5
Again putting x = – 2 and y = 5 in y = mx + 3, we get
5x = m(–2) + 3
⇒ –2m = 5 – 3
⇒ m = – 1
Concept: Algebraic Methods of Solving a Pair of Linear Equations - Substitution Method
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