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Sum
Solve: `("2x" + 3)/5 > ("4x" - 1)/2`, x ∈ W.
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Solution
`("2x" + 3)/5 > ("4x" - 1)/2` , x ∈ W.
⇒ 2(2x + 3) > 5(4x - 1)
⇒ 4x + 6 > 20x - 5
⇒ 4x - 20x > - 5 - 6
⇒ -16x > -11
⇒ x < `(-11)/(-16)` (Dividing by -16)
⇒ x < `11/16`
∴ x = 0
∴ Solution set = {0}
Concept: Replacement Set and Solution Set
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