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Solve: ("2x" + 3)/5 > ("4x" - 1)/2, X ∈ W. - Mathematics

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Sum

Solve: `("2x" + 3)/5 > ("4x" - 1)/2`, x ∈ W.

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Solution

`("2x" + 3)/5 > ("4x" - 1)/2` , x ∈ W.

⇒ 2(2x + 3) > 5(4x - 1)

⇒ 4x + 6 > 20x - 5

⇒ 4x - 20x > - 5 - 6

⇒ -16x > -11

⇒ x < `(-11)/(-16)`   (Dividing by -16)

⇒ x < `11/16`

∴ x = 0

∴ Solution set = {0} 

Concept: Replacement Set and Solution Set
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APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 15 Linear Inequations
Exercise 15 (A) | Q 14 | Page 173
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