Solve : 2/3"X" + 8 < 12; "X" ∈ "W" - Mathematics

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Sum

Solve : `2/3"x" + 8 < 12; "x" ∈ "W"`

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Solution

`2/3"x" + 8 < 12`

⇒ `2/3"x" + 8 - 8 < 12 - 8`

⇒ `2/3"x" < 4`

⇒ `2/3"x" xx 3/2 < 4 xx 3/2`  (Multiplying by `3/2`)

⇒ x < 6

∴ Required answer = {0, 1, 2, 3, 4, 5}

Concept: Replacement Set and Solution Set
  Is there an error in this question or solution?
Chapter 15: Linear Inequations - Exercise 15 (A) [Page 173]

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Selina Concise Mathematics Class 8 ICSE
Chapter 15 Linear Inequations
Exercise 15 (A) | Q 6 | Page 173
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