#### Question

Solve for *x* :

`2/(x+1)+3/(2(x-2))=23/(5x), x!=0,-1,2`

#### Solution

`2/(x+1)+3/(2(x-2))=23/(5x)`

`=>(4(x-2)+3(x+1))/(2(x+1)(x-2))=23/(5x)`

`=>(7x-5)/(2(x^2-x-2))=23/(5x)`

⇒5x(7x−5)=46(x^{2}−x−2)

⇒11x^{2}−21x−92=0

⇒11x^{2}−44x+23x−92=0

⇒11x(x−4)+23(x−4)=0

⇒(11x+23)(x−4)=0

`=>x = -23/11,4`

Is there an error in this question or solution?

Solution Solve for x : 2/(x+1)+3/(2(x-2))=23/(5x), x!=0, -1 ,2 Concept: Solutions of Quadratic Equations by Factorization.