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Solve the Following Quadratic Equations by Factorization: `(X-3)/(X+3)-(X+3)/(X-3)=48/7` , X ≠ 3, X ≠ -3 - CBSE Class 10 - Mathematics

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Question

Solve the following quadratic equations by factorization:

`(x-3)/(x+3)-(x+3)/(x-3)=48/7` , x ≠ 3, x ≠ -3

Solution

We have been given

`(x-3)/(x+3)-(x+3)/(x-3)=48/7`

7(x2 + 9 - 6x - x2 - 9 - 6x) = 48(x2 - 9)

48x2 + 84x - 432 = 0

4x2 + 7x - 36 = 0

Therefore,

4x2 + 16x - 9x - 36 = 0

4x(x + 4) - 9(x + 4) = 0

(4x - 9)(x + 4) = 0

Therefore,

4x - 9 = 0

4x = 9

x = 9/4

or,

x + 4 = 0

x = -4

Hence, x = 9/4 or x = -4.

  Is there an error in this question or solution?

APPEARS IN

Solution Solve the Following Quadratic Equations by Factorization: `(X-3)/(X+3)-(X+3)/(X-3)=48/7` , X ≠ 3, X ≠ -3 Concept: Solutions of Quadratic Equations by Factorization.
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