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# Solve the Following Quadratic Equations by Factorization: Ax2 + (4a2 - 3b)X - 12ab = 0 - Mathematics

Course

#### Question

Solve the following quadratic equations by factorization:

ax2 + (4a2 - 3b)x - 12ab = 0

#### Solution

We have been given

ax2 + (4a2 - 3b)x - 12ab = 0

ax2 + 4a2x - 3bx - 12ab = 0

ax(x + 4a) - 3b(x + 4a) = 0

(ax - 3b)(x + 4a) = 0

Therefore,

ax - 3b = 0

ax = 3b

x=(3b)/a

or

x + 4a = 0

x = -4a

Hence, x=(3b)/a or x = -4a

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#### APPEARS IN

RD Sharma Solution for Class 10 Maths (2018 (Latest))