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Solve the Following Quadratic Equations by Factorization: Ax2 + (4a2 - 3b)X - 12ab = 0 - Mathematics

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Question

Solve the following quadratic equations by factorization:

ax2 + (4a2 - 3b)x - 12ab = 0

Solution

We have been given

ax2 + (4a2 - 3b)x - 12ab = 0

ax2 + 4a2x - 3bx - 12ab = 0

ax(x + 4a) - 3b(x + 4a) = 0

(ax - 3b)(x + 4a) = 0

Therefore,

ax - 3b = 0

ax = 3b

`x=(3b)/a`

or

x + 4a = 0

x = -4a

Hence, `x=(3b)/a` or x = -4a

  Is there an error in this question or solution?

APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.3 | Q: 19 | Page no. 19
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.3 | Q: 19 | Page no. 19
Solution Solve the Following Quadratic Equations by Factorization: Ax2 + (4a2 - 3b)X - 12ab = 0 Concept: Solutions of Quadratic Equations by Factorization.
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