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# If X = − 1 2 ,Is a Solution of the Quadratic Equation 3 X 2 + 2 K X − 3 = 0 ,Find the Value of K. - CBSE Class 10 - Mathematics

ConceptSolutions of Quadratic Equations by Factorization

#### Question

If $x = - \frac{1}{2}$,is a solution of the quadratic equation $3 x^2 + 2kx - 3 = 0$ ,find the value of k.

#### Solution

Since,  $x = - \frac{1}{2}$,is a solution of the quadratic equation  $3 x^2 + 2kx - 3 = 0$

So, it satisfies the given equation.

$\therefore 3 \left( - \frac{1}{2} \right)^2 + 2k\left( - \frac{1}{2} \right) - 3 = 0$

$\Rightarrow \frac{3}{4} - k - 3 = 0$

$\Rightarrow k = \frac{3}{4} - 3$

$\Rightarrow k = \frac{3 - 12}{4}$

$\Rightarrow k = - \frac{9}{4}$

Thus, the value of k is $- \frac{9}{4}$.

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Solution If X = − 1 2 ,Is a Solution of the Quadratic Equation 3 X 2 + 2 K X − 3 = 0 ,Find the Value of K. Concept: Solutions of Quadratic Equations by Factorization.
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