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# If the List Price of a Toy is Reduced by Rs. 2, a Person Can Buy 2 Toys More for Rs. 360. Find the Original Price of the Toy. - CBSE Class 10 - Mathematics

ConceptSolutions of Quadratic Equations by Factorization

#### Question

If the list price of a toy is reduced by Rs. 2, a person can buy 2 toys more for Rs. 360. Find the original price of the toy.

#### Solution

Let the original list price of the toy be Rs. .

Then, the number of toys brought for Rs.360 =360/x

According to question, reduced list price of the toys = Rs. (x - 2).

Therefore, the number of toys brought for Rs.360 =360/(x-2)

It is given that

360/(x-2)-360/x=2

360x-360(x-2)/((x-2)x)=2

(360x-360x+720)/(x^2-2x)=2

720/(x^2-2x)=2

720/2=x^2-2x

360 = x2 - 2x

x2 - 2x - 360 = 0

x2 + 18x - 20x - 360 = 0

x(x + 18) - 20(x + 18) = 0

(x + 18)(x - 20) = 0

x + 18 = 0

x = -18

Or

x - 20 = 0

x = 20

Because cannot be negative.

Thus, x = 20 is the require solution.

Therefore, the original list price of the toy be x = Rs. 20

Is there an error in this question or solution?

#### APPEARS IN

Solution If the List Price of a Toy is Reduced by Rs. 2, a Person Can Buy 2 Toys More for Rs. 360. Find the Original Price of the Toy. Concept: Solutions of Quadratic Equations by Factorization.
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