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If the Equation X2 − Bx + 1 = 0 Does Not Possess Real Roots, Then - Mathematics

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Question

If the equation x2 − bx + 1 = 0 does not possess real roots, then

Options
  • −3 < b < 3

  • −2 < b < 2

  • b > 2

  • b < −2

Solution

The given quadric equation is `x^2 - bx + 1 = 0`, and does not have real roots.

Then find the value of b.

Here,  a = 1, b = -b and ,c = 1

As we know that `D = b^2 - 4ac`

Putting the value of a = 1, b = -b and ,c = 1

`=(-b)^2 - 4 xx 1 xx 1`

`=b^2 - 4`

The given equation does not have real roots, if D < 0 

`b^2 - 4 < 0`

`b^2 < 4`

`b< sqrt4`

`b< ±2`

Therefore, the value of -2 < b< 2 .

  Is there an error in this question or solution?
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APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Q: 11 | Page no. 83
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Q: 11 | Page no. 83
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If the Equation X2 − Bx + 1 = 0 Does Not Possess Real Roots, Then Concept: Solutions of Quadratic Equations by Factorization.
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