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# If the Equation X2 − Bx + 1 = 0 Does Not Possess Real Roots, Then - CBSE Class 10 - Mathematics

ConceptSolutions of Quadratic Equations by Factorization

#### Question

If the equation x2 − bx + 1 = 0 does not possess real roots, then

• −3 < b < 3

• −2 < b < 2

• b > 2

• b < −2

#### Solution

The given quadric equation is x^2 - bx + 1 = 0, and does not have real roots.

Then find the value of b.

Here,  a = 1, b = -b and ,c = 1

As we know that D = b^2 - 4ac

Putting the value of a = 1, b = -b and ,c = 1

=(-b)^2 - 4 xx 1 xx 1

=b^2 - 4

The given equation does not have real roots, if D < 0

b^2 - 4 < 0

b^2 < 4

b< sqrt4

b< ±2

Therefore, the value of -2 < b< 2 .

Is there an error in this question or solution?

#### APPEARS IN

Solution If the Equation X2 − Bx + 1 = 0 Does Not Possess Real Roots, Then Concept: Solutions of Quadratic Equations by Factorization.
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