#### Question

If the equation x^{2} + 4x + k = 0 has real and distinct roots, then

k < 4

k > 4

k ≥ 4

k ≤ 4

#### Solution

The given quadric equation is x^{2} + 4x + k = 0, and roots are real and distinct.

Then find the value of *k.*

Here, a = 1, b = 4 and , c = k

As we know that `D = b^2 - 4ac`

Putting the value of a = 1, b = 4 and , c = k

` (4)^2 - 4 xx 1 xx k `

= 16 - 4k

The given equation will have real and distinct roots, if D > 0

16 - 4k > 0

4k < 16

` k< 16/4`

< 4

Therefore, the value of k < 4 .

Is there an error in this question or solution?

#### APPEARS IN

Solution If the Equation X2 + 4x + K = 0 Has Real and Distinct Roots, Then Concept: Solutions of Quadratic Equations by Factorization.