#### Question

If the equation ax^{2} + 2x + a = 0 has two distinct roots, if

a = ±1

a = 0

a = 0, 1

a = −1, 0

#### Solution

The given quadric equation is ax^{2} + 2x + a = 0 , and roots are distinct.

Then find the value of *a.*

Here, a = a,b = 2 and, c = a

As we know that `D = b^2 - 4ac`

Putting the value of a = a,b = 2 and, c = a

`= (2)^2 - 4 xx a xx a`

`= 4 - 4a^2`

The given equation will have real and distinct roots, if D > 0

`4 -4a^2 = 0`

`4a^2 = 4`

` a^2 = 4/4`

`a = sqrt1`

`= ± 1`

Therefore, the value of ` a = ± 1`.

Is there an error in this question or solution?

#### APPEARS IN

Solution If the Equation Ax2 + 2x + a = 0 Has Two Distinct Roots, If Concept: Solutions of Quadratic Equations by Factorization.